Question 916931
From f(x)=6x^2-36x+59, we see that a = 6, b = -36 and c = 59


This is because the general form is f(x) = ax^2 + bx + c


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Use the <a href="http://www.regentsprep.org/regents/math/algtrig/ate3/discriminant.htm">discriminant formula</a> D = b^2 - 4ac



D = b^2 - 4ac


D = (-36)^2 - 4(6)(59) ... plug in a = 6, b = -36 and c = 59


D = -120



The discriminant is negative, so there are zero real solutions.