Question 916892
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \ln(8x\ +\ 9)\ =\ 5.9]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  e^{\ln(8x\ +\ 9)}\ =\ e^{5.9}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  8x\ +\ 9\ =\ e^{5.9}]


The rest is straight up algebra and calculator work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \