Question 916883
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \sum_{i=0}^2\,\sum_{j=0}^3\,2i\ +\ 3j]


First term of the sum: *[tex \Large i\ =\ 0], *[tex \Large j\ =\ 0]


Second term of the sum:  *[tex \Large i\ =\ 0], *[tex \Large j\ =\ 1]


Third term of the sum: *[tex \Large i\ =\ 0], *[tex \Large j\ =\ 2]


Fourth term: *[tex \Large i\ =\ 0], *[tex \Large j\ =\ 3]


Fifth term: *[tex \Large i\ =\ 1], *[tex \Large j\ =\ 0]


Sixth term: *[tex \Large i\ =\ 1], *[tex \Large j\ =\ 1]


...


Next to the last term: *[tex \Large i\ =\ 2], *[tex \Large j\ =\ 2]


Last term: *[tex \Large i\ =\ 2], *[tex \Large j\ =\ 3]



*[tex \LARGE \ \ \ \ \ \ \ \ \ \  = (2*0+3*0)\ +\ (2*0+3*1)\ +\ (2*0+3*2)\ +\ (2*0+3*3)\ +\ (2*1+3*0)\ +\ ...]


and so on...


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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