Question 916869
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The *[tex \Large y]-intercept is the point *[tex \Large (0,b)] where *[tex \Large b] is the value of the function when *[tex \Large x\ =\ 0].


Plot the vertical asymptote and the horizontal asymptote.  Plot the three intercepts.


Use the two *[tex \Large x]-intercepts and the intersection of the vertical asymptote to divide the *[tex \Large x]-axis into four regions, namely the three intervals *[tex \Large (-\infty,-2)], *[tex \Large (-2,0)],*[tex \Large (0,2)], and *[tex \Large (2,\infty)].  Select a value from each of the intervals and evaluate the function at that value.  The sign of the function value will tell you whether the graph in that region is above or below the *[tex \Large x]-axis.  The graph will tend to infinity (positive or negative depending on the sign of the function in that region as determined above).  As *[tex \Large x] increases or decreases without bound, the graph will tend to the horizontal asymptote.  And the graph will pass through each of the three intercepts that you have plotted.  A rough sketch with these parameters should suffice for your needs.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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