Question 916868
Suppose log a = 0.3, log b = -0.5. Evaluate

log(1000 aČ) 
= log(1000) + log(aČ) 
= 3 + 2 log(a) 
= 3 + 2*0.3 
= 3.6 

I understand everything up until 3+2log(a) after that why does the 2 log(a) become only 0.3? ****************
It doesn't, it's 2 times 0.3
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since 1000 becomes 3*********** 1000 doesn't become 3.  Log(1000) = 3 ********* due to log(base 10) 1000 = 3. Wouldn't the same be true for 2log(a) being something like 2log(base 10)(0.3) and then getting a different answer other than 0.3?
It's 2 times, = 0.6.  You entered it yourself.
Your answer is correct.