Question 916859
Beth is 4 years older than Jane. Sally is twice as old as Jane. Bill is twice as old as Sally. If the sum of their ages is 84 how old is each person?
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Equations:
b = j + 4
s = 2j
b = 2s
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b + j + s = 84
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Substitute:
j+4 + j + (b/2) = 84
Substitute:
2j + 4 + (j+4)/2 = 84
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4j + 8 + j+4 = 168
5j = 156
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j = 31 1/5 (jane's age)
b = j+4 = 35 1/5 (Beth's age)
s = b/2 = 78/5 = 17 3/5 (Sally's age now)
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Cheers,
Stan H.
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