Question 916725
{{{10^(1-x)=2x}}}


{{{log(10,(10^(1-x)))=log(10,2x)}}}


{{{log(10,(10^1)/(10^x))=log(10,2x)}}}


{{{log(10,10^1)-log(10,10^x)=log(10,2x)}}}


{{{log(10,10^1)=log(10,2x)+log(10,10^x)}}}


{{{1=log(10,((2x)(10^x)))}}}


{{{1=log(10,(2x*10^x))}}}


{{{10^1=2x*10^x}}}


{{{2x*10^x=10}}}


{{{x*10^x=5}}}


No way to completely find one formula for x.  Numeric computation to approximately match the left and right sides may be the only way