Question 916637
{{{log(4, ((x+13)/(x-8))) }}} = 1 *[tex \large\ \ log_bx - log_by = log_b(x/y) ]
 *[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]

{{{4^1 = (x+13)/(x-8) }}}
4(x-8) =  x+13
4x - 32 = x+13
3x=  45
x = 15