Question 916560
if it goes through at {{{3}}} bounces at {{{-1}}} and through at {{{2}}}, we will have:
{{{f(x)=(x-3)(x+1)^2(x-2)}}}...when you multiply all this, you will get

{{{f(x)=x^4-3x^3-3x^2+7x+6}}}


 the coefficient of the term with the highest degree (which is {{{x^4}}} or {{{highlight(1)*x^4}}}) is called the leading coefficient: in your case the leading coefficient is {{{highlight(1)}}}


{{{ graph( 600, 600, -15, 15, -15, 15, x^4-3x^3-3x^2+7x+6) }}} 

but, on your image graph goes through points ({{{-1}}},{{{ 0 }}}),({{{1}}},{{{ 0 }}}), ({{{2}}},{{{ 0 }}}), and y-intercept is ({{{ 0 }}},{{{ -2 }}})

so, is this graph http://i.imgur.com/ERfGDlj.png  you need to find equation for?