Question 916455

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-6,-12\right)]. So this means that {{{x[1]=-6}}} and {{{y[1]=-12}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-18,-24\right)].  So this means that {{{x[2]=-18}}} and {{{y[2]=-24}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-24--12)/(-18--6)}}} Plug in {{{y[2]=-24}}}, {{{y[1]=-12}}}, {{{x[2]=-18}}}, and {{{x[1]=-6}}}



{{{m=(-12)/(-18--6)}}} Subtract {{{-12}}} from {{{-24}}} to get {{{-12}}}



{{{m=(-12)/(-12)}}} Subtract {{{-6}}} from {{{-18}}} to get {{{-12}}}



{{{m=1}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-6,-12\right)] and *[Tex \LARGE \left(-18,-24\right)] is {{{m=1}}}



Let me know if you need more help or if you need me to explain a step in more detail.
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Thanks,


Jim