Question 916411
understand almost 90% of how to graph this but there are a few things I don't quiet understand. 
h(x) = (2x+6)(x-3)^2(x+1)^3 
y-int = (0,54) 
x-int = (-3,0)(3,0)(-1,0) 

My question is how do I determine what the degree is?
Multiply the highest powered term in each factor:: x*x^2*x^3 = x^6
 and what the leading coefficient is?:: 2x*x^2*x^3 = 2x^6
LC = 2
------------------------------ 
Also, I am having confusion on what exactly a tangent is can it be thought of like a "straight line" or "the flat spot of a graph on the x-axis"
Tangent to the x-axis means the graph comes to but does not pass thru the axis.
--------------------------
 When I go to graph I understand all the parts except where there there is a flat spot for the x-intercept (-1,0) since it's an odd degree factor shouldn't it just go straight through it and up to the y-intercept? I don't understand the idea of the flattened spots when graphing.
The graph approaches the x axis, lingers close to it, passes thru the axis,
lingers close, then moves away from the axis.
------------------------------------------- 
It would be greatly appreciated if someone could explain this.
{{{graph(400,400,-10,10,-80,120,(2x+6)(x-3)^2(x+1)^3)}}}
----------------
Cheers,
Stan H.