Question 10473


There you go:


2(3y+4)=32 → First you get rid of the ( ) by multiplying 2 with 3y and 4
6y + 8 = 32 | -8 →  Then you isolate 6y by subtracting 8 on both sides of the equation
6y = 24 | :6 →  Now you devide both terms on either side by 6 to get a value for y
y = 12