Question 916249
we are given h(x) = 8 - (3 / (2x+4)) which can be rewritten as
h(x) = (16x-29) / (2x+4)
1)The vertical asymptotes come from the zeroes of the denominator, so I'll set the denominator equal to zero and solve.
2x+4 = 0
x = -2
vertical asymptote is -2
note that the range of the function is (-infinity, -2) and (-2, +infinity) which
implies x = -2 is not allowed
2) Since the degrees of the numerator and the denominator are the same (each being 1), then this rational has a non-zero (non-x-axis) horizontal asymptote; the horizontal asymptote is found by dividing the leading terms:
16x / 2x = 8
horizontal asymptote is 8