Question 916230
 x^2+y^2=169
x^2 + (x-7)^2 = 169
2x^2 -14x + 49 = 169
2x^2 -14x - 120 = 0
x^2 - 7x - 60 = 0
(x + 5)(x - 12)
x = -5, 12
and {{{y = x-7}}}
y = -12, 5
Intersection P(-5,-12) and P(12,5)
{{{drawing(300,300,  -20,20,-20,20,  
 grid(1),
circle(-5, -12,0.6),
circle(12, 5,0.6),
circle(0, 0, 13),
graph( 300, 300, -20,20,-20,20,0, x-7))}}}