Question 915904
*[tex \large 48 = \frac{1}{2} \cdot 12 \cdot 9 \cdot \sin \theta] where theta is the included angle. Solving, we get *[tex \large 48 = 54 \sin \theta \Rightarrow \sin \theta = \frac{8}{9}].


We have *[tex \large \sin^{-1} \frac{8}{9} \approx 1.0949 = 62.73^{\circ}], so that is a solution, and so is *[tex \large 180^{\circ} - 62.73^{\circ}].