Question 10482
1) - x + y = 2
2)   x + y = 4


     0 + 2y = 6  → I added equation 1) to equation 2): -x+x=0, y+y=2y, 2+4=6
     2y = 6 | :2 on both sides
     y = 3  → Now you subsitute y with 3 in equation 2):


x + y = 4
x + 3 = 4 | -3 on both sides
x = 1  → To varify this solution you do the same in equation 1):


-x + y = 2
-x + 3 = 2 | -3 on both sides
-x = -1 | : -1
x = 1  → The solution is varified.


You're welcome. :-)