Question 915464


{{{z[1]= (1-3i)/(4+5i) }}} 

{{{ z[2]= (3-4i)/(5-6i) }}}  


{{{z[1]/z[2]= ((1-3i)/(4+5i))/((3-4i)/(5-6i)) }}}


{{{z[1]/z[2]= ((1-3i)(5-6i))/((4+5i)(3-4i)) }}}


{{{z[1]/z[2]= (1*5-6i-3*5i-3i*(-6i))/(4*3-4*4i+5i*3+5i*(-4i)) }}}


{{{z[1]/z[2]= (5-6i-15i+18i^2)/(12-16i+15i-20i^2) }}}

{{{z[1]/z[2]= (5-21i+18(-1))/(12-i-20(-1)) }}}


{{{z[1]/z[2]= (5-21i-18)/(12-i+20) }}}


{{{z[1]/z[2]= (-13-21i)/(32-i) }}}