Question 915345

let three consecutive odd integers be {{{x}}},{{{x+2}}}, and {{{x+4}}}

given:

the sum of the first two odd integers exceeds the third by {{{9}}}

so, we have

{{{x+(x+2)=x+4+9}}} .solve for .....{{{x}}}

{{{2x+2=x+13}}}

{{{2x-x=13-2}}}

{{{x=11}}}

your integers are: {{{11}}},{{{x+2=13}}}, and {{{x+4=15}}}