<PRE><B>Question 915232</B>
on her way home	speed	x					
onn her way there	speed	x	+	10			
							
	Distance = same		12	miles	1		
	original time – time with increased speed =					1	hour
	t=d/t		

12	/	x	-	12	/	(	x	+	10	)	=	1				
LCD=	x	(	x	+	10	)										
multiply by LCD																
12	(	x	+	10	)	-	12	x	=	1	x	(	x	+	10	)
12	x	+	120	-	12	x	=	1	X^2	+	10	x				
120	=	1	X^2	+	10	x										
1	X^2		+	10	x	-	-120	=	0							
Find roots of the quadratic equation																
a=	1		b=	10		c=	-120									
																
x1=	(	-10	+	sqrt(		100	-	480	))	/	2					
x1=(	-10	+	24.08	)/	2											
x1=	7.04															
																
x2=	(	-7	-	sqrt(		49	-	20	)	/	2					
x2=(	-10	-	24.08	)/	2											
x2=	-17.04															
17.04 m/h, and 7.14 m/h				
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