Question 914919
If you really have two different variables: {{{h}}} and {{{n}}} ,
{{{(sqrt(5))^(8h)=125^(n+5)}}}
{{{((5)^("1 / 2"))^(8h)=(5^3)^(n+5)}}}
{{{5^(("1/2")(8h))=5^(3(n+5))}}}
{{{5^(4h)=5^(3n+15)}}}
{{{4h=3n+15}}}
 
If you really have two different variables: {{{h}}} and {{{n}}} ,
then {{{4h=3n+15}}}--->{{{h=(3n+15)/4}}} is all we can do.
 
If both letters were supposed to be the sane, you would have
{{{4h=3h+15}}}
{{{4h-3h=15}}}
{{{h=15}}}