Question 915091
{{{ ln (x^2) - ln (2) = ln (3x- 4) }}}


{{{ ln (x^2/2)  = ln (3x- 4)}}} if ln same, then


{{{x^2/2  = 3x- 4}}} ..........solve for {{{x}}}


{{{x^2  = 2*3x- 2*4}}}


{{{x^2  = 6x- 8}}}


{{{x^2 -6x+8=0}}}  .....write {{{-6x}}} as {{{-2x-4x}}}


{{{x^2 -2x-4x+8=0}}} ...group


{{{(x^2 -2x)-(4x-8)=0}}}


{{{x(x -2)-4(x-2)=0}}}

{{{(x-4)(x-2)=0}}}


solutions:

if {{{x-4=0}}} => {{{x=4}}}

if {{{x-2=0}}} => {{{x=2}}}


{{{drawing(600, 600, -5, 10, -5, 10,circle(2,0.7,.1),circle(4,2.1,.1), graph( 600, 600, -5, 10, -5, 10, ln (x^2) - ln (2) , ln (3x- 4))) }}}