Question 914957
Ho: u = 150 
Ha: u < 150 (claim)
sample mean (n = 40) = 137, s = 30.20 
z(137) = (137-150)/30.20/sqrt(40) = -2.7225
normalcdf(-100,-2.7225) = .003
5% level of significance...
.003 < .05, reject Ho.
 The test results support the claim.