Question 914778
the sum of two numbers is 91.
12 times the smaller number is 32 more than 8 times the larger.
find the numbers


the sum of two numbers is 91.  let x < y

x+y=91............................(1)

12 times the smaller number is 32 more than 8 times the larger.

12x=32+8y
12x-8y=32
/4
3x-2y=8............................(2)


1	x	+	1	y	=	91	.............1	
								
3	x		-2	y	=	8	.............2	
Eliminate	y							
multiply (1)by		2						
Multiply (2) by		1						
2	x		2	y	=	182		
3	x		-2	y	=	8		
Add the two equations								
5	x				=	190		
/	5							
x	=	38      						
plug value of			x	in (1)				
1	x	+	1	y	=	91		
38		+		y	=	91		
				y	=	91		-38
				y	=	53		
				y	=	53		1
x=	38						
y=	53						
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