Question 914546
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Hi,
*[illustration Sphere.png].
{{{(4/3)pir^3}}} = {{{2.05x10^6mm^3/300x10^6}}}
 r^3 = {{{(3/4)(2.05mm^3/300)/pi }}}
r = {{{root(3,2.05/400pi) }}} = .12mm (nearest one-hundredth)
d = .24mm