Question 914483
By w(x)=x^2/2(1-x), your professor must mean w(x)=x^2/[2(1-x)]={{{x^2/2(1-x)}}} ,
where the 2 and the (1-x) are both in the denominator.
It is not be the same as w(x)=x^2/2*(1-x)={{{(x^2/2)(1-x)}}}
 
Then, for {{{x=0.63}}} ,
{{{w(0.63)=0.63^2/2(1-0.63)=0.3969/(2*0.37)=0.3969/0.74="0.536351352352351..."}}}
 
NOTES:

That long horizontal line/fraction bar in {{{w(x)=x^2/2(1-x)}}} is a grouping symbol, just like the parentheses.


If I had to write that in one line, I would write
w(x)=x^2/[2(1-x)], or w(x)=x^2/2/(1-x), to make it perfectly clear that both, x and (1-x) are dividing {{{x^2}}} .
 
You have to be careful about those "undercover grouping symbols" when entering calculations into a calculator.
Doing calculations one at a time as I showed above may be safer.
To enter {{{w(0.63)=0.63^2/2(1-0.63)}}} into a calculator as one calculation I would enter
0.63 {{{highlight(x^2)}}} {{{highlight("/")}}} {{{highlight("(")}}} 2 {{{highlight(X)}}} {{{highlight("(")}}} 1 {{{highlight("-")}}} 0.63 {{{highlight(")")}}} {{{highlight(")")}}} {{{highlight("=")}}}
or
0.63 {{{highlight(x^2)}}} {{{highlight("/")}}} 2 {{{highlight("/")}}} {{{highlight("(")}}} 1 {{{highlight("-")}}} 0.63 {{{highlight(")")}}} {{{highlight("=")}}}