Question 914474
{{{ln(ln(e^(e^(-20))))^""}}}


{{{ln((e^(-20))*ln(e))}}} Using the rule {{{ln(x^y) = y*ln(x)}}}


{{{ln(e^(-20))+ln(ln(e))}}} Using the rule {{{ln(x*y) = ln(x)+ln(y)}}}


{{{-20*ln(e)+ln(ln(e))}}} Using the rule {{{ln(x^y) = y*ln(x)}}}


{{{-20*1+ln(1)}}} Using the rule {{{ln(e)=1}}}


{{{-20*1+0}}} Using the rule {{{ln(1)=0}}}


{{{-20}}}


So, {{{ln(ln(e^(e^(-20))))^"" = -20}}}


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Thanks,


Jim