Question 914423
I think you got this:

{{{ x^(3/4)-(7x)^(1/4)=0}}} ...if yes, than

{{{ root(4,x^3)-root(4,7x)=0 }}}

{{{ root(4,x^3)=root(4,7x) }}} ..raise both sides to the power of {{{4}}}

{{{ (root(4,x^3))^4=(root(4,7x) )^4}}}

{{{ x^3=7x }}} one solution is {{{x=0}}}

{{{ x^3/x=7 }}}

{{{ x^2=7 }}}

{{{ x=sqrt(7) }}}

other two solutions are :

{{{ x=sqrt(7)=2.65 }}} or {{{ x=-sqrt(7)=2.65 }}}

{{{ graph( 600, 600, -10, 10, -10, 10, x^(3/4)-(7x)^(1/4)) }}}