Question 914392

{{{-2(g-1)=g-4}}} ........first multiply

{{{-2*g-2*(-1)=g-4}}}

{{{-2g+2=g-4}}} ........add {{{2g}}} to both sides


{{{-2g+2g+2=g+2g-4}}}

{{{-cross(2g)+cross(2g)+2=3g-4}}}

{{{2=3g-4}}} ........add {{{4}}} to both sides

{{{2+4=3g-4+4}}}  

{{{6=3g-cross(4)+cross(4)}}}

  {{{6=3g}}}

 {{{6/3=g}}}

 {{{2=g}}}