Question 914267
b, beth now
p, pia now

b=p+6.


{{{(b+5)(p-6)=53}}} according to description.
{{{(p+6+5)(p-6)=53}}} when substitute for b.
{{{(p+11)(p-6)=53}}}
{{{p^2+5p-66=53}}}
{{{p^2+5p-13=0}}}, not factorable.


{{{p=(-5+sqrt(25+4*13))/2}}}
{{{highlight(p=(sqrt(77)-5)/2)}}}


and you can try to simplify for beth's age, {{{highlight(b=(sqrt(77)-5)/2+6)}}}



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{{{sqrt(77)=8.775}}} approx.