Question 914268

parallel lines have {{{same}}}{{{ slope}}}; so, write both equations in slope-intercept form

{{{dx-2y=-8}}} ..........eq.1

{{{dx+8=2y}}}

{{{y=(d/2)x+8/2}}} => slope is {{{(d/2)}}}


{{{2y-5x+1=0}}} ........eq.2

{{{2y=5x-1}}}

{{{y=(5/2)x-1/2 }}}=> slope is {{{(5/2)}}}

so,  

{{{(d/2)= 5/2}}} => {{{d=5}}}


than you have {{{5x-2y=-8}}} or  {{{y=(5/2)x+8/2 }}}


{{{ graph( 600, 600, -10, 10, -10, 10, (5/2)x-1/2, (5/2)x+8/2) }}}