Question 914230
81, 100, 121, 144, 169 are perfect squares


9^2 = 81
10^2 = 100
11^2 = 121
12^2 = 144
13^2 = 169


Notice how we're squaring something each time. The only thing changing is that base (9 to 10 to 11 etc)


So naturally we'd say {{{y=x^2}}} but notice how x = 1 pairs with y = 81. So we can't just say {{{y=x^2}}} because {{{x = 1}}} leads to {{{y = 1}}}


So we have to change the "x" to "x+8" to make sure x = 1 leads to y = 81. We do the +8 to get 1 to 9 (1+8 = 9)


Notice: {{{y=(x+8)^2=(1+8)^2 = 9^2=81}}}


I'll let you try out the others.


So the function is {{{f(x)=(x+8)^2}}}


Let me know if you need more help or if you need me to explain a step in more detail.
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Thanks,


Jim