Question 914206
a triangle has an area of {{{96in^2}}}

=>{{{b*h/2=96in^2}}}

 height {{{h}}} is two-thirds of its base {{{b}}}

=>{{{h= (2/3)b}}}....substitute in

{{{b*h/2=96in^2}}}

{{{(b*(2/3)b)/2=96in^2}}}

{{{b^2*(2/3)=2*96in^2}}}

{{{b^2=2*96in^2/(2/3)}}}

{{{b^2=cross(2)*96in^2/(cross(2)/3)}}}

{{{b^2=3*96in^2}}}

{{{b^2=288in^2}}}

{{{b=sqrt(288in^2)}}}

{{{b=16.97in)}}} (rounded value)


=>{{{ h= (2/3)b }}}=>{{{ h= (2/3)16.97in }}}=> {{{ h=11.31333in}}}