Question 914108
p(had) = .56, n = 30
P( x < 5) = binomcdf(30, .56, 4) 0r P( x < 5) = P(0) + P(1) + P(2) + P(3) + P(4)  
.............
Using Binomial Distribution formula:
Using {{{P (x)= highlight_green(nCx)(p^x)(q)^(n-x) }}} 

p and q are the probabilities of success and failure respectively. 
In this case p = .56 & q = .44, n = 30
{{{nCx = (n!)/x!(n - x)!)}}}