<PRE><B>Question 914015</B>
Weird one

let east bound plane speed =x
north bound plane speed = (x+50)

After 3 hours they have flown at right angles to each othe a distance of 3x &amp;
 3(x+50) miles

At any given time they form a right triangle with the origin

(3(x))^2+(3(x+50))^2 = (2440)^2

/9

(x))^2+(x+50)^2 = (2440)^2/9

x^2+x^2+100x+2500= 661511.11

2x^2+100x-659011.11=0

solve by formula method

to get the value of  x

Find the roots of the equation by quadratic formula							
							
a=	2	,b=	100	,c=	-659011.11		
							
b^2-4ac=	10000	-	-5272088.89				
b^2-4ac=	5282088.89		{{{sqrt(b^2-4ac)=			2298.28	
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-12+21)/(12)}}}							
x1=(	2198.28			)/	4		
x1=	549.57	ft					
x2=(	-100	-2298.28	) /	4			
x2=	-599.57						
Ignore negative value							

Round off

x= 550 plane I

600 = plane II







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