Question 913811
find the focus and directrix. 
{{{y=x^2/16}}}
{{{y-5=(1/4)(x+3)^2}}}
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Basic form of equation for a parabola that applies here:
(x-h)^2=4p(y-k), (h,k)=coordinates of the vertex, p=distance from vertex to focus and to directrix on the axis of symmetry
..
{{{y=x^2/16}}}
x^2=16y
This is a parabola that opens up with vertex at the origin
axis of symmetry: x=0 or y-axis
4p=16
p=4
focus:(0,4)
directrix: y=-4
..
{{{y-5=(1/4)(x+3)^2}}}
(x+3)^2=4(y-5)
This is a parabola that opens up with vertex at (-3,5)
axis of symmetry: x=-3
4p=4
p=1
focus:(-3,6)
directrix: y=4