Question 913594
{{{(2x^(5)y^(-5)z^(-3)) / (8z^(-8)x^(7)y^(6))=(1/4)x^(5-7)y^(-5-6)z^(-3-(-8))}}}
{{{(2x^(5)y^(-5)z^(-3)) / (8z^(-8)x^(7)y^(6))=(1/4)x^(-2)y^(-11)z^(5)}}}
{{{(2x^(5)y^(-5)z^(-3)) / (8z^(-8)x^(7)y^(6))=z^5/(4x^(2)y^(11))}}}