Question 913631
let width be x
length = (x+1)

diagonal is the hypotenuse

Pythagoras theorem

x^2+(x+1)^2=6.5^2

x^2+x^2+2x+1=42.25

2x^2+2x-41.25=0

You have to solve it by formula method

Find the roots of the equation by quadratic formula								
								
a=	2    	b=	2    	c=	-41 1/4			
								
b^2-4ac=	4    	-	-330    					
b^2-4ac=	334    			{{{sqrt(	334    	)}}}=	18 2/7	
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	-2    	+	18 2/7	)/	4    			
x1=	4 1/9							
x2=(	-2    	-18 2/7	) /	4    				
x2=	-5 1/9							
Ignore negative value			mph					
x	=	4 1/9						

width is 4 1/9  feet
length = 5 1/9   feet