Question 913580
Find the vertex of each parabola and graph it.
Basic equation of parabola: 
1. y^2+4x-6y= -1
complete the square:
(y^2-6y+9)+4x=-1+9
(y-3)^2=-4x+8
(y-3)^2=-4(x-2)
Parabola opens left with vertex at(2,3)
..
2. y=x^2+4x+5
complete the square:
y=(x^2+4x+4)-4+5
(x+2)^2=(y-1)
Parabola opens up with vertex at(-2,1)
..
3. y=-x^2-x+1
complete the square:
y=-(x^2+x+1/4)+1/4+1
(x+1/2)^2=-(y-5/4)
Parabola opens down with vertex at(-1/2,5/4)

Sorry, I don't have the means to graph these parabolas