Question 913624
You omitted or do not yet know the target percent of the mixture, so call this T percent salt, by weight.


100(salt/mixture)=T percent


{{{highlight(100*(200*(0.10)+v*(0.20))/(v+200)=T)}}}


The number, T, is expected to be given, but you want to solve for v, assigned as the unknown MASS IN GRAMS of solution B to add.


Study this lesson:   <a href="http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev">http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev</a>