Question 913599
{{{9x^2+9(y^2-(4/3)y)=5}}}
{{{9x^2+9(y^2-(4/3)y+(2/3)^2-(2/3)^2)=5}}}, completing the square for y
{{{9x^2+9((y-2/3)^2-4/9)=5}}}
{{{9x^2+9(y-2/3)^2-4=5}}}
{{{9x^2+9(y-2/3)^2=9}}}
Divide both members by 9.
{{{x^2+(y-2/3)^2=9=3^2}}}


Radius is 3;
Center is (0, 2/3)