Question 913580
Number 1 has a horizontal axis of symmetry; and the other parabolas are routine.  This help will be for number 1.


{{{4x=-y^2+6y-1}}}
Complete The Square for y.
{{{4x=-1(y^2-6y+1)}}}, use {{{(-6/2)^2=9}}}.
{{{4x=-1(y^2-6y+9+1-9)}}}
{{{4x=-1((y-3)^2-8)}}}
{{{x=-(1/4)((y-3)^2-8)}}}
{{{highlight(x=-(1/4)(y-3)^2+2)}}}, now in standard form for parabola with horizontal axis of symmetry.


This parabola is squashed horizontally, and is concave to the left.  Vertex is (2, 3).