Question 913408


{{{f(x) = (x + 2)^2 -9}}}


{{{f(x) = x^2 +4x+4 -9}}}

{{{f(x) = x^2 +4x -5}}}

{{{f(x) = x^2 -x+5x -5}}}

{{{f(x) = (x^2 -x)+(5x -5)}}}

{{{f(x) = x(x -1)+5(x -1)}}}

{{{f(x) = (x +5)(x -1)}}}

{{{f(x) =0}}} if  {{{ (x +5)(x -1)=0}}}


{{{ x +5=0}}} =>{{{x=-5}}}
{{{ x -1=0}}} =>{{{x=1}}}

so, answer is:

C) {{{1}}}, {{{-5}}}