Question 913381
Perpendicular line slopes are negative reciprocals.
{{{m*(3)=-1}}}
{{{m=-1/3}}}
Use the point-slope form,
{{{y-4=-(1/3)(x-1)}}}
{{{y-4=-(1/3)x+1/3}}}
{{{y=-(1/3)x+1/3+12/3}}}
{{{y=-(1/3)x+13/3}}}