Question 77256
{{{y = x^2 - 4x + 1}}}
This can be solved by completing the square (add 4 and subtract 4)
{{{y = x^2 -4x + 4 + 1 - 4}}}
{{{y = (x - 2)^2 - 3}}}
The axis of symmetry is halfway between the 2 roots (where y = 0)
What values of x makes y = 0?
{{{x = 2 +-sqrt(3)}}} make y = 0
To find the point halfway between
{{{x = 2 + sqrt(3)}}} and
{{{x = 2 - sqrt(3)}}}
add them and divide by 2
The answer is x = 2
That is the equation of the line