Question 913344

{{{ln(e^-20* ln (e) )}}}                 

= {{{ln(e^-20)+ln( ln (e) )}}}

= {{{ln(e^-20)+ln( ln (e) )}}}    .............  {{{ln(e^-20)=-20}}} and  {{{ln( ln (e) )=0}}}

so, {{{ln(e^-20 *ln e) =-20}}}


{{{log(7/2)=log(7)-log(2)=0.84509-0.3010299=0.54406}}}