Question 913303
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
{{{log(14, 14^(11))}}} = 11
{{{log(3, (1/27)))}}} = -3, 3^(-3) = 1/27
{{{log(27, sqrt(3)))}}} = x = 1/6 (see following)
  27^x = 3^(1/2)
 3^3x = 3^(1/2)
3x = 1/2
x = 1/6
.....
{{{log(10, 10^(x)) = x}}} 
10^42