Question 77324
The given function is: 


f(x) = 3sinx + 2cos2x   


To find the value of f(pi/2) 



Substituting for x, we get: 



f(Pi/2) = 3 Sin (pi/2) + 2 Cos(2(pi/2))  -------------(1)


We know that the value of 


Sin(pi/2) = 1 and cos (pi) = -1 


Hence, the equation becomes...



f(pi/2) = 3 (1) + 2 (-1)  



f(pi/2) = 3 - 2  



f(pi/2) = 1



Hence, the solution.