Question 912307
Let {{{u=4^x}}}
{{{u+1/u=4}}}
{{{u^2+1=4u}}}
{{{u^2-4u+1=0}}}
{{{u^2-4u+4+1=4}}}
{{{(u-2)^2=3}}}
{{{u-2=0 +- sqrt(3)}}}
{{{u=2 +- sqrt(3)}}}
{{{4^x=2 +- sqrt(3)}}}
{{{x=log(4,(2 +- sqrt(3)))}}}
{{{x=log((2 +- sqrt(3)))/log((4))}}}