Question 913219
AE bisects  angle A

let each bisected angle be x 

angle A = 2x

Similarly let y be each of the bisected angle
2y = angle B

2x+2y = 180 deg ( adjacent angles of a parallelogram)

x+y = 90

In triangle ABE

x +y + angle AEB = 180 deg. ( sum of angles of a triangle)

90+angle AEB = 180 deg
angle AEB = 180-90
Angle AEB = 90 deg