Question 77322
If the velocity can be obtained by multiplying t by 32 and we add 10 we have

v=32t+10


If you want the equation in function notation then:


v(t)=32t+10


So if t=0, we have an initial velocity of v=10. If v=1, then we have a velocity of v=32+10=42. If we have v=2, then v=32*2+10=64+10=74. In other words, for each second the velocity increases by 32 (notice how 32+42=74). So 32 is our rate of increase and 10 is our initial velocity.